HEB100 Calculation 1
The cross-section of the HEB100 in the picture is a coincidence and, as it was later confirmed, also a result of luck. The calculation related to the cross-section HEB100 was formed later here as an example. Without changing the situation in any way, when the selection is directed to other cross-sections. The HEB100 cross-section presented here, it's a good idea for us to get to know it first.
Bending case 1
Often, an allowable deflection is assigned to a profitable profile, but the profile is not specified. In these calculations, it is often forgotten to calculate the deflection caused by the profile's own weight. By calculating the static values corresponding to the deflection. Forgetting to calculate the profile's own weight can lead to a problem that you don't know in advance about the planned object.
From the technical tables we get the static values for the profiles, based on which we calculate the deflection for the related load case. We do this with "clear dimensioning", which we consider to also include the deflection of the profile due to its own weight. In some of the cases I've looked at, this has simply been ignored.
The table below for the HEB100 cross-section gives static values of the deflection, which takes into account the load and also the deflection caused by the beam's weight. Without forgetting the magnitude of the bending stress determined by the table at different spans. The tables presented elsewhere for strength calculation do not do this.
Span
The table shows the span length 518 cm for the HEB100 cross-section when the load F1 is in the middle of the beam and the deflection ratio is 1: 1000. The bending stress is 2.2 kN /cm2.
Bending Stress
HEB100 F1 1:1000 = 50 x 10 = 500 cm (in the table 518 cm)
Bending stress = 2,2 kN/cm2
Profile L1000 σt Ix Wx Iy Wy Area
Item cm kN/cm2 cm4 cm3 cm4 cm3 kg/m A cm2
HEB100 518 2,2 450 90 167 33,5 20,4 26
Deflection Ratio 1:1000
f= 500 cm / 1000 = 0.5 cm - f= 518 cm / 1000 = 0.52 cm
The deflection f is the span divided by the deflection ratio.
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1
1 1
Pascal's triangle
1.0 - 1.1(2) - 1.25
If the load is evenly distributed over the length of the support, the span can be extended to 1.1 times. The bending ratio of 1:1000 remains unchanged, but the bending stress is reduced by 25%. This also applies to other cross-sections. Please read more ==>
22.12.2023*013:00 (314 - 40559)
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