Axial DeformationAksiaalinen puristumaF = 1 kN L = 100 cm A = 5 cm2 ό = 0,001 E = 20 600 kN / cm4 Basic load is always 1 kN Length 100 cm is easy to remenber Deformation 0,001 cm Beam cm F kN ==> ==================== <== kNό = 100 cm x 1 kN x cm2 = 0,001 cm 20600 kN x 5 cm2 The formula calculates steel deformation and elongation, without need to understand the calculation. EPC calculation requires an output value, which is the formula does not require. EPC CalculationExample 1F = 200 kN => FΔ = 200 (x 1 kN) L = 500 cm => LΔ = 5 (x 100 cm) A = 50 cm2 => AΔ = 10 (x 5 cm2) ό = 0,001 x FΔ x LΔ = 0,001 x 200 x 5 = 0,09708 1,03 x AΔ 1,03 x 10 Example 2F = 1200 kN L = 800 cm A = 315 cm2 ό = ? ό = 0,001 x FΔ x LΔ = 0,001 x 1200 x 8 = 0,1479 1,03 x AΔ 1,03 x 63 (Spread sheet calculation gives 0,1479) Example 3F = 0,3 kN L = 20 cm A = 1 cm2 ό = ? ό = 0,001 x FΔ x LΔ = 0,001 x 0,3 x 0,2 = 0,000291 1,03 x AΔ 1,03 x 0,2 (Spread sheet calculation gives 0,0003) Calculate the other cases, having the same procedure and accuracy. 21.6 2018*08:00 (919 - 779) |