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finnish_translation.jpgHEB 100 as Pascal's Triangle 2

HEB 100 Pascalin kolmiona 2

European wide flange beam. Dimensions according to EN 1025

HEB100_Pascals_triangle.jpg

2-tukinen_kannatus_pienin.jpg

The matter's deflection of the concentrated force

                                                            F = 1 kN

                                                               ||

                                                               ||      Force

                                                              \  /

                                   =======================

                                   /\                                              /\

                    The profile deflection of the concentrated force (= load)

 
Length                           Pascal's Triangle                       Deflection    
HEB 100 -1                                      1
HEB 100 -1.1                              1       1
HEB 100 -1.21                         1      2       1
HEB 100 -1.331                     1    3      3      1
HEB 100 -1.4641                1     4     6     4      1         0,9803 cm/0.7366 cm = 1.331
          758 cm                   ==============           0.9803 cm     1.331
          689 cm                     ============             0.7366 cm      1.331
          627 cm                         =========                0.5534 cm      1.331
          570 cm                          =======                    0.4158 cm      1.331
          518 cm                               ===                        0.3124 cm         - _  
            1.1                                  Factors                                            1.331
 
We could use both 518 cm or 519 cm for the calculation. The Choice was 518 cm. Deflection of the matter, is proporotional value of Phi 3.14
          519 cm                               ===                             0.3142 cm          - _
                                                                                         3.1415926.....
 
Example: Deflection of the concentrated force
F = 1 kN
f = F x L3 / 48 x I x E
f = 0.3142 cm
 
Profile      L1000      σt           Ix          Wx          Iy         Wy                    Area
Nimike       cm      kN/cm2     cm4          cm3           cm4        cm3      kg/m    A cm2
HEB100      518         2.2         450          90         167       33.5       20.4      26
 
We started from proportional value of phi and we finished on the fift row to the proportional value of gravity force 9,82. This, if we want so think.
 
758 cm                   ==============              0.9803 cm

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18.2.2012*15:19 (761 - 43942)
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