HEB100 Bending Case 1

Profile L1000 σt Ix Wx Iy Wy A
Nimike cm kN/cm2 cm4 cm3 cm4 cm3 kg/m cm2
HEB100 518 2.2 450 90 167 33.5 20.4 26
I F 1 kN I V :::::::::::::::::::::::::::::::::::: / \ / \
<------------ l="" --="" -------="">
Span
The table is valid when the concentrated force is in the middle of the girder. This is bending case 1. L1000 is the span lenght, when the deflection/ span ratio is 1:1000. This includes the weight of the girder and loading. When the span increases 1.1 times longer, deflection increase 1.331 and bending stress 1.12 times.
1
1 1
1 2 1
1 3 3 1
The knowledge from the table
HEB100 F1 1:1000 => L518 cm
HEB100 F1 1:1000 => σt 2.2 kN/cm2
σt = Bending stress
1.________1:800_____________________
1:800 deflection ratio, deflection/span
HEB100 F1 1:800 = L518 cm
L = 1.1 x 518 = 570 cm
f = 1.331 x 0.52 cm = 0.69 cm
(Calculation program 0.71 cm)
f = deflection
L = span
HEB100 F1 1:800 = σt 1.12 x 2.2 kN/cm2
σt = 2.5 kN/cm2
(Calculation program 2.5 kN/cm2)
2.___________1:630_________________
HEB100 F1 1:630 = L1.12 x 518cm
L = 627 cm
f = 1.3312 x 0.52 cm = 0.92
(Calculation program 0.99 cm)
HEB100 F1 1:630 => σt 1.122 x 2.2 kN/cm2
σt = 2.8 kN/cm2
(Calculation program 2,8 kN/cm2)
3.__________1:500__________________
HEB100 F1 1:500 = L1.13 x 518 cm
L = 689 cm
f = 1.3313 x 0.52 cm = 1.23 cm
(Calculation program 1.37cm)
HEB100 F1 1:500 => σt 1.123 x 2.2 kN/cm2
σt = 3-1 kN/cm2
(Calculation program 3.2 kN/cm2)
4._________1:400___________________
HEB100 F1 1:400 = L1.14 x 518 cm
L = 758 cm
f = 1.3314 x 0.52 cm = 1.63 cm
(Calculation program 1.91 cm)
HEB100 F1 1:400 => σt 1.124 x 2.2 kN/cm2
σt = 3.5 kN/cm2
(Calculation program 3.7 kN/cm2)
5.__________1:315_________________
HEB100 F1 1:315 = L1.15 x 518 cm
L = 834 cm
f = 1.3315 x 0.52 cm = 2.2 cm
(Calculation program 2.7 cm)
HEB100 F1 1:315 => σt 1.125 x 2.2 kN/cm2
σt = 3.9 kN/cm2
(Calculation program 4.3 kN/cm2)
6._________1:250_________________
HEB100 F1 1:315 = L1.16 x 518 cm
L = 918 cm
f = 1.3316 x 0.52 cm = 2.9 cm
(Calculation program 3.7 cm)
HEB100 F1 1:315 => σt 1.126 x 2.2 kN/cm2
σt = 4.3 kN/cm2
(Calculation program 4.9 kN/cm2)
.... 2.5 - 3.15 - 4.0 - 5.0 - 6.3 - 8.0 - 10
When understanding the exponential structure of the phenomena, it can be shaped without formula.

10.9.2012*11:23 (43928 - 813) www.karikolehmainen.com epcalculation@gmail.com
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