HEB I-Profiles 1 kN Load Bearing

HEB I-profiilien 1 kN kuorman kantaminen

European wide flange beams DIN 1025 - EN10034 

1.1   Tabled Span when the Deflection Ratio 1:1000

                        L cm              Load 1 kN                                                     

HEB100           518                The known length when deflection ratio 1:1000

HEB120*          644               1.25 x 100 = 125

                                              1.25  x 518 cm   =  647 cm

HEB140           761                span 761 cm when deflection ratio 1:1000)

                                              1.12 x 647 cm = 724 cm

HEB160           868               1.25 x 125 x 1.03(28)** = 160 mm

                                              1.25  x 647 x 1.03 cm  =  833 cm

                                               1.25 x 1.25 x 1.0328 = 1.618

HEB180           968                span 968 cm when deflection ratio 1:000

                                              1.12 x 833 cm = 933 cm

HEB200         1062                1.25 x 160 = 200 mm

                                               1.25  x 833. cm  =  1041 cm

HEB220         1150                1.12 x 200 = 220 mm

                                              1.12  x 1041 cm =  1166 cm

HEB260         1316                (240 + 260) /2 = 250 = 1.25 x200

                                               1.25  x 1041 cm = 1301 cm

                                               The calculation is so far the accurate 

________________________________________________________________

* The standards do not recognize the size of 125 mm, so this corresponds to size 120 mm. I-profile height of 120 mm is smaller than the height 100 mm x 1,25 = 125 mm. Despite of this, the span length error is only 3.5 cm, the proportional error of 0.0054.

** The Universal friction coefficient in other words time dilation factor 1.0328 when the speed of light 0.25 x c, cannot have many decimals in these kind of calculations, so the two decimals precision is enough. 

Load 1 kN

2.  Proportion Numbers

1 - 1.03 - 1.06 - 1.12 - 1.25 - 1.6 - 2 - 2.5

3.  Standard Numbers

100 - 125 - 160

4.  The Fifth Row of Pascal's Triangle

1,4641 x 1,1 = 1,6105

5.  E = m c²

Momentum p is transformed into Lorenz - variant factor 1/L when L = sqrt (1-( v/c )²)

==>    time dilation 1.0328 when the speed of light 0,25 c

1d x 2d x time dilation = 1.618

1.25 x 1.25 x 1.0328 = 1.618

1d x 2d x 3d x time dilation = 2

1.25 x 1.25 x 1.25 x 1.0328 = 2

1d = one-dimensional diameter

2d = two-dimensional cross-section

3d = Three-dimensional object

We are living in 3d-world, so the Pascal's triangle row factor

1.1 = 1.0328³ = 1.1

6.   Dimensionalities in the Calculation

                           1

 1d                 1         1                                              Length

 2d            1,       2        1        x  1,03 = 1,25            Surface

               Pascal's Triangle

Surface factor x Fatique factor = General Fatiquing Factor (Universal friction)